In the figure, SLNR and SLMQ are parallelograms. Given that ∠NLP = 11°, ∠SRQ = 69° and SQR is an isosceles triangle where SQ = SR. Find
- ∠LPN
- ∠SLP
(a)
∠LNR
= 180° - 69°
= 111° (Interior angles)
∠LPN
= 180° - 111° - 11°
= 58° (Angles sum of triangle)
(b)
∠SLP
= ∠LPN
= 58° (Alternate angles)
Answer(s): (a) 58°; (b) 58°