In the figure, PHKN and PHJM are parallelograms. Given that ∠KHL = 14°, ∠PNM = 60° and PMN is an isosceles triangle where PM = PN. Find
- ∠HLK
- ∠PHL
(a)
∠HKN
= 180° - 60°
= 120° (Interior angles)
∠HLK
= 180° - 120° - 14°
= 46° (Angles sum of triangle)
(b)
∠PHL
= ∠HLK
= 46° (Alternate angles)
Answer(s): (a) 46°; (b) 46°