In the figure, GACF and GABE are parallelograms. Given that ∠CAD = 12°, ∠GFE = 60° and GEF is an isosceles triangle where GE = GF. Find
- ∠ADC
- ∠GAD
(a)
∠ACF
= 180° - 60°
= 120° (Interior angles)
∠ADC
= 180° - 120° - 12°
= 48° (Angles sum of triangle)
(b)
∠GAD
= ∠ADC
= 48° (Alternate angles)
Answer(s): (a) 48°; (b) 48°