In the figure, GACF and GABE are parallelograms. Given that ∠CAD = 11°, ∠GFE = 68° and GEF is an isosceles triangle where GE = GF. Find
- ∠ADC
- ∠GAD
(a)
∠ACF
= 180° - 68°
= 112° (Interior angles)
∠ADC
= 180° - 112° - 11°
= 57° (Angles sum of triangle)
(b)
∠GAD
= ∠ADC
= 57° (Alternate angles)
Answer(s): (a) 57°; (b) 57°