In the figure, TMPS and TMNR are parallelograms. Given that ∠PMQ = 12°, ∠TSR = 73° and TRS is an isosceles triangle where TR = TS. Find
- ∠MQP
- ∠TMQ
(a)
∠MPS
= 180° - 73°
= 107° (Interior angles)
∠MQP
= 180° - 107° - 12°
= 61° (Angles sum of triangle)
(b)
∠TMQ
= ∠MQP
= 61° (Alternate angles)
Answer(s): (a) 61°; (b) 61°