In the figure, UNQT and UNPS are parallelograms. Given that ∠QNR = 12°, ∠UTS = 74° and UST is an isosceles triangle where US = UT. Find
- ∠NRQ
- ∠UNR
(a)
∠NQT
= 180° - 74°
= 106° (Interior angles)
∠NRQ
= 180° - 106° - 12°
= 62° (Angles sum of triangle)
(b)
∠UNR
= ∠NRQ
= 62° (Alternate angles)
Answer(s): (a) 62°; (b) 62°