In the figure, LEGK and LEFJ are parallelograms. Given that ∠GEH = 12°, ∠LKJ = 67° and LJK is an isosceles triangle where LJ = LK. Find
- ∠EHG
- ∠LEH
(a)
∠EGK
= 180° - 67°
= 113° (Interior angles)
∠EHG
= 180° - 113° - 12°
= 55° (Angles sum of triangle)
(b)
∠LEH
= ∠EHG
= 55° (Alternate angles)
Answer(s): (a) 55°; (b) 55°