In the figure, VPRU and VPQT are parallelograms. Given that ∠RPS = 13°, ∠VUT = 65° and VTU is an isosceles triangle where VT = VU. Find
- ∠PSR
- ∠VPS
(a)
∠PRU
= 180° - 65°
= 115° (Interior angles)
∠PSR
= 180° - 115° - 13°
= 52° (Angles sum of triangle)
(b)
∠VPS
= ∠PSR
= 52° (Alternate angles)
Answer(s): (a) 52°; (b) 52°