In the figure, KDFJ and KDEH are parallelograms. Given that ∠FDG = 15°, ∠KJH = 65° and KHJ is an isosceles triangle where KH = KJ. Find
- ∠DGF
- ∠KDG
(a)
∠DFJ
= 180° - 65°
= 115° (Interior angles)
∠DGF
= 180° - 115° - 15°
= 50° (Angles sum of triangle)
(b)
∠KDG
= ∠DGF
= 50° (Alternate angles)
Answer(s): (a) 50°; (b) 50°