In the figure, SLNR and SLMQ are parallelograms. Given that ∠NLP = 10°, ∠SRQ = 62° and SQR is an isosceles triangle where SQ = SR. Find
- ∠LPN
- ∠SLP
(a)
∠LNR
= 180° - 62°
= 118° (Interior angles)
∠LPN
= 180° - 118° - 10°
= 52° (Angles sum of triangle)
(b)
∠SLP
= ∠LPN
= 52° (Alternate angles)
Answer(s): (a) 52°; (b) 52°