In the figure, MFHL and MFGK are parallelograms. Given that ∠HFJ = 15°, ∠MLK = 77° and MKL is an isosceles triangle where MK = ML. Find
- ∠FJH
- ∠MFJ
(a)
∠FHL
= 180° - 77°
= 103° (Interior angles)
∠FJH
= 180° - 103° - 15°
= 62° (Angles sum of triangle)
(b)
∠MFJ
= ∠FJH
= 62° (Alternate angles)
Answer(s): (a) 62°; (b) 62°