In the figure, WQSV and WQRU are parallelograms. Given that ∠SQT = 10°, ∠WVU = 74° and WUV is an isosceles triangle where WU = WV. Find
- ∠QTS
- ∠WQT
(a)
∠QSV
= 180° - 74°
= 106° (Interior angles)
∠QTS
= 180° - 106° - 10°
= 64° (Angles sum of triangle)
(b)
∠WQT
= ∠QTS
= 64° (Alternate angles)
Answer(s): (a) 64°; (b) 64°