In the figure, UNQT and UNPS are parallelograms. Given that ∠QNR = 12°, ∠UTS = 64° and UST is an isosceles triangle where US = UT. Find
- ∠NRQ
- ∠UNR
(a)
∠NQT
= 180° - 64°
= 116° (Interior angles)
∠NRQ
= 180° - 116° - 12°
= 52° (Angles sum of triangle)
(b)
∠UNR
= ∠NRQ
= 52° (Alternate angles)
Answer(s): (a) 52°; (b) 52°