In the figure, GACF and GABE are parallelograms. Given that ∠CAD = 11°, ∠GFE = 69° and GEF is an isosceles triangle where GE = GF. Find
- ∠ADC
- ∠GAD
(a)
∠ACF
= 180° - 69°
= 111° (Interior angles)
∠ADC
= 180° - 111° - 11°
= 58° (Angles sum of triangle)
(b)
∠GAD
= ∠ADC
= 58° (Alternate angles)
Answer(s): (a) 58°; (b) 58°