In the figure, LEGK and LEFJ are parallelograms. Given that ∠GEH = 13°, ∠LKJ = 64° and LJK is an isosceles triangle where LJ = LK. Find
- ∠EHG
- ∠LEH
(a)
∠EGK
= 180° - 64°
= 116° (Interior angles)
∠EHG
= 180° - 116° - 13°
= 51° (Angles sum of triangle)
(b)
∠LEH
= ∠EHG
= 51° (Alternate angles)
Answer(s): (a) 51°; (b) 51°