In the figure, KDFJ and KDEH are parallelograms. Given that ∠FDG = 13°, ∠KJH = 79° and KHJ is an isosceles triangle where KH = KJ. Find
- ∠DGF
- ∠KDG
(a)
∠DFJ
= 180° - 79°
= 101° (Interior angles)
∠DGF
= 180° - 101° - 13°
= 66° (Angles sum of triangle)
(b)
∠KDG
= ∠DGF
= 66° (Alternate angles)
Answer(s): (a) 66°; (b) 66°