In the figure, KDFJ and KDEH are parallelograms. Given that ∠FDG = 16°, ∠KJH = 61° and KHJ is an isosceles triangle where KH = KJ. Find
- ∠DGF
- ∠KDG
(a)
∠DFJ
= 180° - 61°
= 119° (Interior angles)
∠DGF
= 180° - 119° - 16°
= 45° (Angles sum of triangle)
(b)
∠KDG
= ∠DGF
= 45° (Alternate angles)
Answer(s): (a) 45°; (b) 45°