In the figure, ZTVY and ZTUX are parallelograms. Given that ∠VTW = 16°, ∠ZYX = 73° and ZXY is an isosceles triangle where ZX = ZY. Find
- ∠TWV
- ∠ZTW
(a)
∠TVY
= 180° - 73°
= 107° (Interior angles)
∠TWV
= 180° - 107° - 16°
= 57° (Angles sum of triangle)
(b)
∠ZTW
= ∠TWV
= 57° (Alternate angles)
Answer(s): (a) 57°; (b) 57°