In the figure, KDFJ and KDEH are parallelograms. Given that ∠FDG = 13°, ∠KJH = 75° and KHJ is an isosceles triangle where KH = KJ. Find
- ∠DGF
- ∠KDG
(a)
∠DFJ
= 180° - 75°
= 105° (Interior angles)
∠DGF
= 180° - 105° - 13°
= 62° (Angles sum of triangle)
(b)
∠KDG
= ∠DGF
= 62° (Alternate angles)
Answer(s): (a) 62°; (b) 62°