In the figure, VPRU and VPQT are parallelograms. Given that ∠RPS = 14°, ∠VUT = 62° and VTU is an isosceles triangle where VT = VU. Find
- ∠PSR
- ∠VPS
(a)
∠PRU
= 180° - 62°
= 118° (Interior angles)
∠PSR
= 180° - 118° - 14°
= 48° (Angles sum of triangle)
(b)
∠VPS
= ∠PSR
= 48° (Alternate angles)
Answer(s): (a) 48°; (b) 48°