In the figure, LEGK and LEFJ are parallelograms. Given that ∠GEH = 11°, ∠LKJ = 78° and LJK is an isosceles triangle where LJ = LK. Find
- ∠EHG
- ∠LEH
(a)
∠EGK
= 180° - 78°
= 102° (Interior angles)
∠EHG
= 180° - 102° - 11°
= 67° (Angles sum of triangle)
(b)
∠LEH
= ∠EHG
= 67° (Alternate angles)
Answer(s): (a) 67°; (b) 67°