In the figure, SLNR and SLMQ are parallelograms. Given that ∠NLP = 16°, ∠SRQ = 61° and SQR is an isosceles triangle where SQ = SR. Find
- ∠LPN
- ∠SLP
(a)
∠LNR
= 180° - 61°
= 119° (Interior angles)
∠LPN
= 180° - 119° - 16°
= 45° (Angles sum of triangle)
(b)
∠SLP
= ∠LPN
= 45° (Alternate angles)
Answer(s): (a) 45°; (b) 45°