In the figure, QJLP and QJKN are parallelograms. Given that ∠LJM = 16°, ∠QPN = 79° and QNP is an isosceles triangle where QN = QP. Find
- ∠JML
- ∠QJM
(a)
∠JLP
= 180° - 79°
= 101° (Interior angles)
∠JML
= 180° - 101° - 16°
= 63° (Angles sum of triangle)
(b)
∠QJM
= ∠JML
= 63° (Alternate angles)
Answer(s): (a) 63°; (b) 63°