In the figure, GACF and GABE are parallelograms. Given that ∠CAD = 11°, ∠GFE = 75° and GEF is an isosceles triangle where GE = GF. Find
- ∠ADC
- ∠GAD
(a)
∠ACF
= 180° - 75°
= 105° (Interior angles)
∠ADC
= 180° - 105° - 11°
= 64° (Angles sum of triangle)
(b)
∠GAD
= ∠ADC
= 64° (Alternate angles)
Answer(s): (a) 64°; (b) 64°