Given that ABCD is a trapezium and ABD is an isosceles triangle, find the values of
- ∠n
- ∠p
(a)
∠n
= 180° - 85°
= 95° (Interior angles)
(b)
∠DBA
= 85° ÷ 2
= 42.5° (Exterior angle of a triangle)
∠CDB = ∠DBA = 42.5° (Alternate angles)
∠p
= 180° - 89° - 42.5°
= 48.5° (Angles sum of triangle)
Answer(s): (a) 95°; (b) 48.5°