Given that NPQR is a trapezium and NPR is an isosceles triangle, find the values of
- ∠a
- ∠b
(a)
∠a
= 180° - 83°
= 97° (Interior angles)
(b)
∠RPN
= 83° ÷ 2
= 41.5° (Exterior angle of a triangle)
∠QRP = ∠RPN = 41.5° (Alternate angles)
∠b
= 180° - 88° - 41.5°
= 50.5° (Angles sum of triangle)
Answer(s): (a) 97°; (b) 50.5°