Given that NPQR is a trapezium and NPR is an isosceles triangle, find the values of
- ∠y
- ∠z
(a)
∠y
= 180° - 85°
= 95° (Interior angles)
(b)
∠RPN
= 85° ÷ 2
= 42.5° (Exterior angle of a triangle)
∠QRP = ∠RPN = 42.5° (Alternate angles)
∠z
= 180° - 89° - 42.5°
= 48.5° (Angles sum of triangle)
Answer(s): (a) 95°; (b) 48.5°