Given that EFGH is a trapezium and EFH is an isosceles triangle, find the values of
- ∠e
- ∠f
(a)
∠e
= 180° - 84°
= 96° (Interior angles)
(b)
∠HFE
= 84° ÷ 2
= 42° (Exterior angle of a triangle)
∠GHF = ∠HFE = 42° (Alternate angles)
∠f
= 180° - 89° - 42°
= 49° (Angles sum of triangle)
Answer(s): (a) 96°; (b) 49°