Given that CDEF is a trapezium and CDF is an isosceles triangle, find the values of
- ∠c
- ∠d
(a)
∠c
= 180° - 86°
= 94° (Interior angles)
(b)
∠FDC
= 86° ÷ 2
= 43° (Exterior angle of a triangle)
∠EFD = ∠FDC = 43° (Alternate angles)
∠d
= 180° - 90° - 43°
= 47° (Angles sum of triangle)
Answer(s): (a) 94°; (b) 47°