Given that HJKL is a trapezium and HJL is an isosceles triangle, find the values of
- ∠c
- ∠d
(a)
∠c
= 180° - 85°
= 95° (Interior angles)
(b)
∠LJH
= 85° ÷ 2
= 42.5° (Exterior angle of a triangle)
∠KLJ = ∠LJH = 42.5° (Alternate angles)
∠d
= 180° - 90° - 42.5°
= 47.5° (Angles sum of triangle)
Answer(s): (a) 95°; (b) 47.5°