Given that GHJK is a trapezium and GHK is an isosceles triangle, find the values of
- ∠q
- ∠r
(a)
∠q
= 180° - 83°
= 97° (Interior angles)
(b)
∠KHG
= 83° ÷ 2
= 41.5° (Exterior angle of a triangle)
∠JKH = ∠KHG = 41.5° (Alternate angles)
∠r
= 180° - 89° - 41.5°
= 49.5° (Angles sum of triangle)
Answer(s): (a) 97°; (b) 49.5°