Given that ABCD is a trapezium and ABD is an isosceles triangle, find the values of
- ∠q
- ∠r
(a)
∠q
= 180° - 86°
= 94° (Interior angles)
(b)
∠DBA
= 86° ÷ 2
= 43° (Exterior angle of a triangle)
∠CDB = ∠DBA = 43° (Alternate angles)
∠r
= 180° - 90° - 43°
= 47° (Angles sum of triangle)
Answer(s): (a) 94°; (b) 47°