Given that MNPQ is a trapezium and MNQ is an isosceles triangle, find the values of
- ∠h
- ∠i
(a)
∠h
= 180° - 85°
= 95° (Interior angles)
(b)
∠QNM
= 85° ÷ 2
= 42.5° (Exterior angle of a triangle)
∠PQN = ∠QNM = 42.5° (Alternate angles)
∠i
= 180° - 90° - 42.5°
= 47.5° (Angles sum of triangle)
Answer(s): (a) 95°; (b) 47.5°