Given that CDEF is a trapezium and CDF is an isosceles triangle, find the values of
- ∠y
- ∠z
(a)
∠y
= 180° - 83°
= 97° (Interior angles)
(b)
∠FDC
= 83° ÷ 2
= 41.5° (Exterior angle of a triangle)
∠EFD = ∠FDC = 41.5° (Alternate angles)
∠z
= 180° - 89° - 41.5°
= 49.5° (Angles sum of triangle)
Answer(s): (a) 97°; (b) 49.5°