Given that NPQR is a trapezium and NPR is an isosceles triangle, find the values of
- ∠s
- ∠t
(a)
∠s
= 180° - 86°
= 94° (Interior angles)
(b)
∠RPN
= 86° ÷ 2
= 43° (Exterior angle of a triangle)
∠QRP = ∠RPN = 43° (Alternate angles)
∠t
= 180° - 90° - 43°
= 47° (Angles sum of triangle)
Answer(s): (a) 94°; (b) 47°