Given that HJKL is a trapezium and HJL is an isosceles triangle, find the values of
- ∠t
- ∠v
(a)
∠t
= 180° - 83°
= 97° (Interior angles)
(b)
∠LJH
= 83° ÷ 2
= 41.5° (Exterior angle of a triangle)
∠KLJ = ∠LJH = 41.5° (Alternate angles)
∠v
= 180° - 88° - 41.5°
= 50.5° (Angles sum of triangle)
Answer(s): (a) 97°; (b) 50.5°