Given that ABCD is a trapezium and ABD is an isosceles triangle, find the values of
- ∠w
- ∠x
(a)
∠w
= 180° - 83°
= 97° (Interior angles)
(b)
∠DBA
= 83° ÷ 2
= 41.5° (Exterior angle of a triangle)
∠CDB = ∠DBA = 41.5° (Alternate angles)
∠x
= 180° - 89° - 41.5°
= 49.5° (Angles sum of triangle)
Answer(s): (a) 97°; (b) 49.5°