Given that PQRS is a trapezium and PQS is an isosceles triangle, find the values of
- ∠a
- ∠b
(a)
∠a
= 180° - 84°
= 96° (Interior angles)
(b)
∠SQP
= 84° ÷ 2
= 42° (Exterior angle of a triangle)
∠RSQ = ∠SQP = 42° (Alternate angles)
∠b
= 180° - 88° - 42°
= 50° (Angles sum of triangle)
Answer(s): (a) 96°; (b) 50°