Given that BCDE is a trapezium and BCE is an isosceles triangle, find the values of
- ∠j
- ∠k
(a)
∠j
= 180° - 84°
= 96° (Interior angles)
(b)
∠ECB
= 84° ÷ 2
= 42° (Exterior angle of a triangle)
∠DEC = ∠ECB = 42° (Alternate angles)
∠k
= 180° - 90° - 42°
= 48° (Angles sum of triangle)
Answer(s): (a) 96°; (b) 48°