Given that PQRS is a trapezium and PQS is an isosceles triangle, find the values of
- ∠h
- ∠i
(a)
∠h
= 180° - 86°
= 94° (Interior angles)
(b)
∠SQP
= 86° ÷ 2
= 43° (Exterior angle of a triangle)
∠RSQ = ∠SQP = 43° (Alternate angles)
∠i
= 180° - 88° - 43°
= 49° (Angles sum of triangle)
Answer(s): (a) 94°; (b) 49°