Given that PQRS is a trapezium and PQS is an isosceles triangle, find the values of
- ∠p
- ∠q
(a)
∠p
= 180° - 85°
= 95° (Interior angles)
(b)
∠SQP
= 85° ÷ 2
= 42.5° (Exterior angle of a triangle)
∠RSQ = ∠SQP = 42.5° (Alternate angles)
∠q
= 180° - 90° - 42.5°
= 47.5° (Angles sum of triangle)
Answer(s): (a) 95°; (b) 47.5°