In the figure, S is the centre of a semicircle and SNPQ is a rhombus. Given that ∠SQR = 27°, find
- ∠g
- ∠h
(a)
∠SQR
= ∠SRQ
= 27° (Isosceles triangle)
∠QSR
= 180° - 27° - 27°
= 126° (Angles sum of triangle)
∠g
= ∠QSR
= 126° (Corresponding angles)
(b)
∠h
= 180° - 126°
= 54° (Interior angles)
Answer(s): (a) 126°; (b) 54°