In the figure, K is the centre of a semicircle and KFGH is a rhombus. Given that ∠KHJ = 26°, find
- ∠j
- ∠k
(a)
∠KHJ
= ∠KJH
= 26° (Isosceles triangle)
∠HKJ
= 180° - 26° - 26°
= 128° (Angles sum of triangle)
∠j
= ∠HKJ
= 128° (Corresponding angles)
(b)
∠k
= 180° - 128°
= 52° (Interior angles)
Answer(s): (a) 128°; (b) 52°