In the figure, L is the centre of a semicircle and LGHJ is a rhombus. Given that ∠LJK = 29°, find
- ∠p
- ∠q
(a)
∠LJK
= ∠LKJ
= 29° (Isosceles triangle)
∠JLK
= 180° - 29° - 29°
= 122° (Angles sum of triangle)
∠p
= ∠JLK
= 122° (Corresponding angles)
(b)
∠q
= 180° - 122°
= 58° (Interior angles)
Answer(s): (a) 122°; (b) 58°