In the figure, Q is the centre of a semicircle and QLMN is a rhombus. Given that ∠QNP = 29°, find
- ∠g
- ∠h
(a)
∠QNP
= ∠QPN
= 29° (Isosceles triangle)
∠NQP
= 180° - 29° - 29°
= 122° (Angles sum of triangle)
∠g
= ∠NQP
= 122° (Corresponding angles)
(b)
∠h
= 180° - 122°
= 58° (Interior angles)
Answer(s): (a) 122°; (b) 58°