In the figure, E is the centre of a semicircle and EABC is a rhombus. Given that ∠ECD = 28°, find
- ∠q
- ∠r
(a)
∠ECD
= ∠EDC
= 28° (Isosceles triangle)
∠CED
= 180° - 28° - 28°
= 124° (Angles sum of triangle)
∠q
= ∠CED
= 124° (Corresponding angles)
(b)
∠r
= 180° - 124°
= 56° (Interior angles)
Answer(s): (a) 124°; (b) 56°