In the figure, Z is the centre of a semicircle and ZVWX is a rhombus. Given that ∠ZXY = 29°, find
- ∠q
- ∠r
(a)
∠ZXY
= ∠ZYX
= 29° (Isosceles triangle)
∠XZY
= 180° - 29° - 29°
= 122° (Angles sum of triangle)
∠q
= ∠XZY
= 122° (Corresponding angles)
(b)
∠r
= 180° - 122°
= 58° (Interior angles)
Answer(s): (a) 122°; (b) 58°