In the figure, S is the centre of a semicircle and SNPQ is a rhombus. Given that ∠SQR = 26°, find
- ∠r
- ∠s
(a)
∠SQR
= ∠SRQ
= 26° (Isosceles triangle)
∠QSR
= 180° - 26° - 26°
= 128° (Angles sum of triangle)
∠r
= ∠QSR
= 128° (Corresponding angles)
(b)
∠s
= 180° - 128°
= 52° (Interior angles)
Answer(s): (a) 128°; (b) 52°