In the figure, S is the centre of a semicircle and SNPQ is a rhombus. Given that ∠SQR = 28°, find
- ∠k
- ∠m
(a)
∠SQR
= ∠SRQ
= 28° (Isosceles triangle)
∠QSR
= 180° - 28° - 28°
= 124° (Angles sum of triangle)
∠k
= ∠QSR
= 124° (Corresponding angles)
(b)
∠m
= 180° - 124°
= 56° (Interior angles)
Answer(s): (a) 124°; (b) 56°