In the figure, J is the centre of a semicircle and JEFG is a rhombus. Given that ∠JGH = 31°, find
- ∠e
- ∠f
(a)
∠JGH
= ∠JHG
= 31° (Isosceles triangle)
∠GJH
= 180° - 31° - 31°
= 118° (Angles sum of triangle)
∠e
= ∠GJH
= 118° (Corresponding angles)
(b)
∠f
= 180° - 118°
= 62° (Interior angles)
Answer(s): (a) 118°; (b) 62°